f(x) = x-3m(x) = 2x²-x-15Makaf(x) ÷ m(x) =(x-3) ÷ (2x²-x-15) =(x-3) ÷ (½(2x....)(2x....)) =(x-3) ÷ (x²-x-15(2)) =(x-3) ÷ (x²-x-30) =dua faktor yg saat dikali = -30ditambah = -1, adalah-6 dan 5(x-3) ÷ (½(2x-6)(2x+5)) =(x-3) ÷ ((x-3)(2x+5)) =¹/₂ₓ₊₅ jawaban D. ¹/₂ₓ₊₅
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f(x) = x-3
m(x) = 2x²-x-15
Maka
f(x) ÷ m(x) =
(x-3) ÷ (2x²-x-15) =
(x-3) ÷ (½(2x....)(2x....)) =
(x-3) ÷ (x²-x-15(2)) =
(x-3) ÷ (x²-x-30) =
dua faktor yg saat dikali = -30
ditambah = -1, adalah
-6 dan 5
(x-3) ÷ (½(2x-6)(2x+5)) =
(x-3) ÷ ((x-3)(2x+5)) =
¹/₂ₓ₊₅
jawaban D. ¹/₂ₓ₊₅