Question

2(x-3)+y=3 dan 3(x-3)-y=7

pakek jalan eliminasi...

Answer 1

2(x-3)+y=3
2x - 6 + y = 3
2x + y = 3 + 6
2x + y = 9.......> pers 1

3(x -3 ) -y = 7
3x - 9 - y = 7
3x - y = 7 + 9
3x - y = 16.....> pers II

Eliminasi :
2x + y = 9
3x - y = 16 +
5x = 25
x = 5

2x + y = 9
2*5 + y = 9
10 + y = 9
y = 9-10
y = -1


 

Answer 2

2x-6+y=3
2x+y=9....1
3x-9-y=7
3x-y=16...2

2x+y=9 x 3
3x-y=16 x 2
6x+3y=27
6x-2y=32
5y=- 5
y=-1
2x+y=9
2x-1=9
2x=9+1
2x=10
x=5