Question

Yang bisa tlong bantu.integral -4 / (2x -3) ^ 3 dx

Answer 1

Int  -4/(2x-3)³  dx
misal u = 2x - 3
du = 2 dx
-------------- (x) -2
-2 du = -4 dx
so,
= int  -2/u³  du
= int  -2u^-3  du
= -2 *  (-1/2) u^-2 + C
= u^-2 + C
= 1/u²  + C
= 1/(2x-3)² + C