Tolong d bantu ya :)
ini pakek aturan rantai
tentukan turunan fungsi-fungsi berikt:
a. f(x): 5-3x/4x+7
b. f(x): 2x-3/x^2=4x-1
c. f(x): 2x^2+3x+2/2x-10
ini pakek aturan rantai
tentukan turunan fungsi-fungsi berikt:
a. f(x): 5-3x/4x+7
b. f(x): 2x-3/x^2=4x-1
c. f(x): 2x^2+3x+2/2x-10
f'(x) = -3(4x+7) - (5-3x)(4)
(4x+7)²
= -12x -21 -20 + 12x
(4x-7)²
= -41
(4x-7)²
b. f(x): 2x-3/x^2=4x-1
f(x)⇒ 2x-3 = 4x³ - x²
f(x) = 4x³ + 3x -3 = 0
f'x) = 12x² -3 = 0
x² = 3/12 = 1/4 maka x = +- 1/2
c. f(x): 2x^2+3x+2/2x-10
f(x) = 2x² + 3x + 2
2(x - 5)
f'(x) = (4x + 3)(2x - 10) - (2x² + 3x + 2)(2)
2² (x - 5)²
= 8x² - 34x - 30 - 4x² - 6x - 4
4(x - 5)²
= 4x² - 44x - 34
4(x - 5)²
= 2x² -22x - 17
2(x - 5)²