Question

1/2(3p-1) < 5
1/4(5y-1) > 1/3(2y+1)
1/3(x+2) +1/2(x-1) >1

Answer 1

1) 1/2(3p-1) < 5
kdua ruas dikali 2 didapat :
3p-1 < 10
3p < 10+1
3p < 11
p < 11/3
p < 3 2/3



2) 1/4(5y-1) > 1/3(2y+1)
kdua ruas dikali 12 didapat :
3(5y-1) > 4(2y+1)
15y-3 > 8y+4
15y-8y > 4+3
7y > 7
y > 7/7 ----> y > 1


3)1/3(x+2) + 1/2(x-1) > 1
kdua ruas dikali 6 didapat :
2(x+2) + 3(x-1) > 6
2x+4 + 3x-3 > 6
5x+1 > 6
5x > 6-1
5x > 5
x > 5/5
x > 1