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ΔT = 110 -10 = 100 derajat
kalor yg dibutuhkan = 20.000 J
c = ?
kalor = m . c . ΔT
20.000 = 0,5 . c . 100
20.000 = 50 .c
20.000/50 = c
400 = c
jadi kalor jenis tembaga adalah 400 kg/J derajat C