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Verified answer
2cos²x - 1 + sin (½π - 2x) = 0cos 2x + sin (90-2x) = 0
cos 2x + cos 2x = 0
2 cos 2x = 0
cos 2x = 0
cos 2x = cos 90°
2x = 90°
x = 45°
dan
cos 2x = cos 270°
2x = 270°
x = 135°