Bentuk sederhana dari
(2x+ y/2)^(minus 1) [(2x)^(minus 1)+(y/2)^(minus 1)]
a. 1
b. x^y-1
c.x^(minus 1 )y
d.xy
e.(xy)^(minus 1)
(2x+ y/2)^(minus 1) [(2x)^(minus 1)+(y/2)^(minus 1)]
a. 1
b. x^y-1
c.x^(minus 1 )y
d.xy
e.(xy)^(minus 1)
Takamori37
Penyelesaian:
![$\begin{align}(2x+y/2)^{-1}\left[(2x)^{-1}+(y/2)^{-1}\right]&=\frac{1}{2x+y/2}\left[\frac{1}{2x}+\frac{1}{y/2}\right] \\ &=\frac{1}{2x+y/2}\times\frac{2x+y/2}{(2x)(y/2)} \\ &=\frac1{(2x)(y/2)} \\ &=\frac1{xy} \\ &=(xy)^{-1}\ \ [E]\end{align}](https://tex.z-dn.net/?f=%24%5Cbegin%7Balign%7D%282x%2By%2F2%29%5E%7B-1%7D%5Cleft%5B%282x%29%5E%7B-1%7D%2B%28y%2F2%29%5E%7B-1%7D%5Cright%5D%26%3D%5Cfrac%7B1%7D%7B2x%2By%2F2%7D%5Cleft%5B%5Cfrac%7B1%7D%7B2x%7D%2B%5Cfrac%7B1%7D%7By%2F2%7D%5Cright%5D+%5C%5C+%26%3D%5Cfrac%7B1%7D%7B2x%2By%2F2%7D%5Ctimes%5Cfrac%7B2x%2By%2F2%7D%7B%282x%29%28y%2F2%29%7D+%5C%5C+%26%3D%5Cfrac1%7B%282x%29%28y%2F2%29%7D+%5C%5C+%26%3D%5Cfrac1%7Bxy%7D+%5C%5C+%26%3D%28xy%29%5E%7B-1%7D%5C+%5C+%5BE%5D%5Cend%7Balign%7D "$\begin{align}(2x+y/2)^{-1}\left[(2x)^{-1}+(y/2)^{-1}\right]&=\frac{1}{2x+y/2}\left[\frac{1}{2x}+\frac{1}{y/2}\right] \\ &=\frac{1}{2x+y/2}\times\frac{2x+y/2}{(2x)(y/2)} \\ &=\frac1{(2x)(y/2)} \\ &=\frac1{xy} \\ &=(xy)^{-1}\ \ [E]\end{align}")
3 votes
Thanks 3
arildajeline13
keren,,,makasih ya kak
Takamori37
Iya, sama-sama.
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