Question

2logx + 2log(x-1) < 1

Answer 1

2'log x + 2'log (x-1)  < 2'log 2
syrat x > 0  atau x-1 > 0 --> x > 1
syrat pembatas  x > 1
x(x-1) -2 < 0
..
x(x-1) < 2
x^2 -x - 2 < 0
(x-2)(x+1) < 0
x >  2 atau x < -1