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(x² - 8x + 12) ≥ (1/2)^-5
x² - 8x + 12 ≥ 32
x² - 8x - 20 ≥ 0
(x + 2)(x - 10) ≥ 0
x yg memenuhi adalah x ≥ 10
1/2log (x-6)(x-2) = -5
1/2 log (x-6)(x-2) = 1/2 log 1/2 ^-5
ingat a.loga = 1
a.log a pangkat 3 = 1 x 3
coret 1/2log nya
(x-6)(x-2) = ½^-5
lanjutkan sendiri oke