Question

2log5+2log8-2log25+2log5

Answer 1

Saya coba jawab ya ⇩⇩

²log 5 + ²log 8 - ²log 25 + ²log 5
= ²log (5) + ²log (2³) - ²log (5²) + ²log (5)
= ²log (5) + ²log₂ (3) - ²log₂ (5) + ²log (5)
= log (5) + 3 - ²log₂ (5) + ²log (5)
= ²log₁(5) + 3-2log (5) + ²log₁(5)
= (1 - 2 + 1 ) ²log (5) + 3
= 0 ²log (5) + 3
= 0 + 3
= 3 ← jawaban

Answer 2

²㏒5 + ²㏒8- ²㏒25 + ²㏒5
=²㏒ 5×8×5/25
=²㏒ 200/25
=²㏒ 8
=3

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