Question

2log3=a
3log5=b
nilai dari 3log300 jika dinyatakan dalam a dan b...

Answer 1

Log 300 / log 3
= ^3 log 300 / ^3log 3.
= ^3 log (5.3.2.5.2) / ^3log 3
= ^3 log 5 + ^3 log 3 + ^3 log 2 + ^3 log 5 + ^3 log 2 / 1
= (b + 1 + 1/a + b + 1/a) X a
= ab + a + 1 + ab + 1
= 2ab + a + 2.