Question

2log3 = a & 3log5 = b
tentukan 30log150 dalam a dan b..... !

Answer 1

²log 3 = a
³log 2 = 1/a
³log 5 = b

^30log 150
=³log 150 / ³log 30
=(³log 2×3×5²) / (³log 2×3×5)
=(³log 2+³log 3+ ³log 5²) / (³log 2+³log 3+ ³log 5)
= (³log 2+³log 3+ 2 ³log 5) / (³log 2+³log 3+ ³log 5)
=(1/a+1+2b) / (1/a+1+b)
=[(1+a+2ab)/a] / [(1+a+ab)/a]
=(1+a+2ab)/(1+a+ab)