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logx^2 - log3 = log (x+6)
log((x^2)/3) = log (x+6) => log di kiri dan di kanan sama tewas (hilang)
(x^2)/3 = (x+6)
x^2 = 3(x+6)
x^2 = 3x+18
x^2 - 3x - 18 = 0
(x-6)(x+3)=0
Maka nilai x nya:
1. x-6=0 => x=6
2. x+3=0 => x=-3