Question

2log(×-4)+2log(×-2)=3

Answer 1

^2log(x-4)+^2log(x-2) = ^2log8
^2log(x-4)(x-2) = ^2log8
(x-4)(x-2) = 8
x^2 -6x +8 = 8
x^2 - 6x +8-8 = 0
x^2 -6x = 0
x(x-6) =0
x = 0

atao
x-6 = 0
x = 6

Answer 2

^2 log (x-4) + 2 log (x-2) = 3
^2 log (x-4) (x-2) = ^2 log 8
(x-4) ( x-2) = 8
x²-6x+8-8 = 0
x²-6x = 0
x ( x-6) = 0
x = 6