2.Jaka liczbe cząsteczek stanowi 0,4g NaOH
M(NaOH)=23+16+1=40 g/mol
40 g --- 6,02·10²³ cząsteczek
0,4 g --- x
x= 6,02·10²¹ cząsteczek
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M(NaOH)=23+16+1=40 g/mol
40 g --- 6,02·10²³ cząsteczek
0,4 g --- x
x= 6,02·10²¹ cząsteczek