Penjelasan dengan langkah-langkah:
sudut lancip = 0 ≤ x ≤ π/2 (kuadran I)
tan = de/sa
•tan a = 3/4
depan = 3
samping = 4
maka dengan menggunakan rumus phytagoras didapatkan miring = 5
sehingga :
sin a = de/mi = 3/5
cos a = sa/mi = 4/5
•tan b = 1/√2
depan = 1
samping = √2
miring = √(1² + √2²)
miring = √1 + 2
miring = √3
sin b = de/mi
sin b = 1/√3
cos b = sa/mi = √2/√3
cos (a + b) = cos a.cosb - sina.sinb
cos (a+b) = 4/5 . √2/√3. - 3/5 . 1/√3
cos (a + b) = 4√2/5√3 - 3/5√3
cos (a + b) = (4√2 - 3)/5√3
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Penjelasan dengan langkah-langkah:
sudut lancip = 0 ≤ x ≤ π/2 (kuadran I)
tan = de/sa
•tan a = 3/4
depan = 3
samping = 4
maka dengan menggunakan rumus phytagoras didapatkan miring = 5
sehingga :
sin a = de/mi = 3/5
cos a = sa/mi = 4/5
•tan b = 1/√2
depan = 1
samping = √2
miring = √(1² + √2²)
miring = √1 + 2
miring = √3
sin b = de/mi
sin b = 1/√3
cos b = sa/mi = √2/√3
cos (a + b) = cos a.cosb - sina.sinb
cos (a+b) = 4/5 . √2/√3. - 3/5 . 1/√3
cos (a + b) = 4√2/5√3 - 3/5√3
cos (a + b) = (4√2 - 3)/5√3