Question

2b + 3c = 85
3b + 1c = 75
menggunakan metode eliminasi

Answer 1

1c=c
2b+3c=85  |x1|  => 2b+3c=85
3b+c=75  |x3| =>    9b+3c=225
                             -----------------  --
                             -7b  = -140
                                   b= 20
=> 2b+3c = 85 (b dmasukkan 20 )
  = 2 (20) + 3c = 85
= 40+3c=85
   = 3c = 85-40
   = 3c = 45
   = c= 15

Answer 2

3b+1c=75 |x3|
2b+3c=85|x1|
_______-
v
v

9b+3c=225
2b+3c=85
________-
7b=140
b=20
c= ?

2b+3c=85
2.20+3c=85
3c=85-40
3c=45
c=45/3
c=15