[tex]t=\frac{1}{2}ak^2-1|+1\\t+1=\frac{1}{2}ak^2|:\frac{1}{2}a\\\frac{t+1}{\frac{1}{2}a}=k^2|\sqrt{}\\k=\sqrt{\frac{t+1}{\frac{1}{2}a}}[/tex]
Odpowiedź:
Szczegółowe wyjaśnienie:
t = [tex]\frac{1}{2}[/tex]a[tex]k^{2}[/tex] - 1 / + 1
t + 1 = [tex]\frac{1}{2}[/tex]a[tex]k^{2}[/tex] / · 2
2(t + 1) = a[tex]k^{2}[/tex] / : a
[tex]\frac{2(t+1)}{a}[/tex] = k² / √
k = [tex]\sqrt{\frac{2(t+1)}{a} }[/tex]
I wszystko OK
Pozdrawiam
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[tex]t=\frac{1}{2}ak^2-1|+1\\t+1=\frac{1}{2}ak^2|:\frac{1}{2}a\\\frac{t+1}{\frac{1}{2}a}=k^2|\sqrt{}\\k=\sqrt{\frac{t+1}{\frac{1}{2}a}}[/tex]
Verified answer
Odpowiedź:
Szczegółowe wyjaśnienie:
t = [tex]\frac{1}{2}[/tex]a[tex]k^{2}[/tex] - 1 / + 1
t + 1 = [tex]\frac{1}{2}[/tex]a[tex]k^{2}[/tex] / · 2
2(t + 1) = a[tex]k^{2}[/tex] / : a
[tex]\frac{2(t+1)}{a}[/tex] = k² / √
k = [tex]\sqrt{\frac{2(t+1)}{a} }[/tex]
I wszystko OK
Pozdrawiam