Luas selimut kerucut tersebut adalah 204,1 cm²
Langkah langkah
s² = r² + t²
s² = 5² + 12²
s² = 25 + 144
s² = 169
s = √169
s = 13 cm
L selimut = π × r × s
L selimut = 3,14 × 5 × 13
L selimut = 204,1 cm²
s² = 5²+12²
= 25+144
= 169
s = √169=13
luas selimut kerucut = π.r.s
= 3,14 x 5 x 13
= 204,1 cm²
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Luas selimut kerucut tersebut adalah 204,1 cm²
Langkah langkah
s² = r² + t²
s² = 5² + 12²
s² = 25 + 144
s² = 169
s = √169
s = 13 cm
L selimut = π × r × s
L selimut = 3,14 × 5 × 13
L selimut = 204,1 cm²
s² = 5²+12²
= 25+144
= 169
s = √169=13
luas selimut kerucut = π.r.s
= 3,14 x 5 x 13
= 204,1 cm²