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logaritma -> a log n = b
5log125 = 3, karena 5∧3 = 125
3log 1/27 = -3, karena 3∧-3 = 1/27
2. 3 log 1/27 =3 log 1 - 3 log 27
= 0 - 3 log 3^3 (sifat log a log 1 = 0)
= 0 - 3 = -3