Question

(729pangkat1/3 *
32pangkat3/5)pangkat1/2 =

Answer 1

((3^6)^(1/3) x (2^5)^(3/5))^(1/2)
= (3^2 x 2^3)^(1/2)
= 3 x 2 √2
= 6√2

ket: ^ = pangkat

Answer 2

(729*1/3 × 32*3/5)*1/2 = {(9*3)*1/3 × (2*5)*3/5}*1/2
                                 = (9 × 2*3)*1/2
                                 = (9 × 8)*1/2
                                 = 72*1/2