Question

27. Hasil dari integrate 3x² + 2x - 4 dx.​

Answer 1

Materi : Integral

3x² + 2x - 4

= ( 3/3 )x³ + ( 2/2 )x² - ( 4/1 )x + C

= (1)x³ + (1)x² - (4)x + C

= x³ + x² - 4x + C { c. ? }

Semoga bisa membantu

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Answer 2

Verified answer

Jawab:

C. x³ + x² - 4x + C

Penjelasan dengan langkah-langkah:

Rumus Integral parsial:

[tex]\boxed{\frac{a}{n+1}x^{n+1} + \:C}[/tex]

a = koefisien x

n = pangkat

[tex]\displaystyle\int 3x^{2} + 2x - 4 \: \:dx[/tex]

[tex]3x^{2} = \frac{3}{2+1}x^{2+1} = \frac{3}{3}x^{3} = x^{3}[/tex]

[tex]2x = 2x^{1} = \frac{2}{1+1}x^{1+1} = \frac{2}{2}x^{2} = x^{2}[/tex]

[tex]4 = 4x^{0} = \frac{4}{0+1}x^{0+1} = \frac{4}{1}x^{1} = 4x[/tex]

Maka:

[tex]\displaystyle\int 3x^{2} + 2x - 4 \: \:dx[/tex]

= x³ + x² - 4x + C

Jadi, hasil dari [tex]\int 3x^{2} + 2x - 4 \: \:dx[/tex]  adalah x³ + x² - 4x + C  (C)