Question

27 °F =..... R=... C.... K


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Answer 1

27°F =(-2,3)°R = (-2,8)°C = 27,6K


27°F = °R

27°F = 4/9 × (t-32)°R

27°F = 4/9 × (27-32)°R

27°F = 4/9 × (-5)°R

27°F = (-20)/9°R

27°F = (-2,3)°R


27°F = °C

27°F = 5/9 × (t-32)°C

27°F = 5/9 × (27-32)°C

27°F = 5/9 × (-5)°C

27°F = (-25)/9°C

27°F = (-2,8)°C


27°F = K

27°F = 5/9 × (t-32) + 273K

27°F = 5/9 × (27-32) + 273K

27°F = 5/9 × (-5) + 273K

27°F = 248/9K

27°F = 27,6K