Question

A. 3log (243/27)
b. Jika diketahui log 2 = 0,301, log 3 = 0,477, maka nilai log 6 adalah ....

Answer 1

A . ³log 
=³log243 - ³log 27
=³log - ³log
=³log3 + ³log3 + ³log3 + ³log3 + ³log3 - ³log3 -  ³log3 -  ³log3
=1 + 1 + 1 + 1 + 1 - 1 - 1 - 1
= 5 - 3
= 2

B. log 2 = 0,301
log 3 = 0,477

log 6 = log (2 . 3)
=log2 + log3
=0,301 + 0,477
=0,778

Semoga membantu...............