Odpowiedź:
[tex]a_1=54\\\displaystyle q=\frac{18}{54} =\frac{1}{3} \\a_n=a_1\cdot q^{n-1}\\54\cdot\left(\frac{1}{3} \right)^{n-1}=\frac{2}{27} /\cdot\frac{1}{54} \\\left(\frac{1}{3} \right)^{n-1}=\frac{1}{729} \\\left(\frac{1}{3} \right)^{n-1}=\left(\frac{1}{3} \right)^6\\n-1=6\\n=7[/tex]
Siódmym wyrazem
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Odpowiedź:
[tex]a_1=54\\\displaystyle q=\frac{18}{54} =\frac{1}{3} \\a_n=a_1\cdot q^{n-1}\\54\cdot\left(\frac{1}{3} \right)^{n-1}=\frac{2}{27} /\cdot\frac{1}{54} \\\left(\frac{1}{3} \right)^{n-1}=\frac{1}{729} \\\left(\frac{1}{3} \right)^{n-1}=\left(\frac{1}{3} \right)^6\\n-1=6\\n=7[/tex]
Siódmym wyrazem