Question

Jika m memenuhi persamaan (2m+1)/6+(2m+1)/2=6,maka nilai 2m+1 adalah

Answer 1

(2m+1)/6 + (2m+1)/2 = 6
(2m+1)6 + (6m+3)/6 =6
(8m+4)/6 = 6
8m + 4 =6 x 6
8m +4 = 36
8m = 32
m = 4

2m + 1
= 2(4) +1 
= 9

Answer 2

Jwb :
(2m + 1)/6 + (2m + 1)/2 = 6

(ruas kiri dan ruas kanan dikalikan 6 untuk menghilangkan bentuk pecahan)

(2m + 1) + 3(2m + 1) = 36
2m + 1 + 6m + 3 = 36
8m + 4 = 36
8m = 36 - 4
8m = 32
m = 32/8 = 4

jadi, nilai 2m + 1 = 2(4) + 1 = 8+1 = 9


semoga bisa membantu ^_^