Question

2+6+10+...+k=200
nilai k adlah??
a.10
b.34
c.36
d.38
pke caranya jg yh

Answer 1

A= 2
b = 4

Sn = n/2. (2a + (n-1)b)
200 = n/2.(4+ (n-1)4
200 = n/2. (4 + 4n -4)----> kalikan 2 biar pecahannya ilang
200 = n/2 ( 4n)
400 = 4n^2
n^2 = 400/4 = 100
n =√100 = 10

U10 = K = a + (n-1)b
             = 2 + 9.4
             = 38.....(D)

Answer 2

Jawabanya d. itu bedanya masing masing 4 .pake logika biar cepet.