Question

(2√5+3√2)(3√5√-2√2)=

Answer 1

(2√5+3√2)(3√5-2√2)
= (2√5x3√5)+(2√5×(-2√2))+(3√2×3√5)+(3√2×(-2√2))
=(2×3)(√5×√5)+(2×(-2))(√5×√2)+(3×3)(√2×√5)+(3×(-2))(√2×√2)
=(6×5)+(-4)(√10)+9(√10)+(-6)(2)
=30-4√10+9√10-12
=30-12+(-4+9)√10
=18+5√10