25. Jumlah sudut dalam sebuah segitiga = 180° Besar susut ABC = 180 – (4x + 10) Besar sudut ACB = 180 – (5x + 5) sudut ABC + sudut ACB + sudut BAC = 180°↔ 180 – (4x + 10) + 180 – (5x + 5) + 60 = 180 ↔ 180 – 4x – 10 + 180 – 5x – 5 + 60 = 180 ↔ 180 – 10 + 180 – 5 + 60 – 180 = 4x + 5x ↔ 225 = 9x ↔ x = 225/9 = 25 Besar sudut ABC = 180 – (4x + 10)= 180 – 4x – 10 = 170 – 4(25) = 170 – 100 = 70 Jawab: C 26 dan 27, gambar tidak jelas.
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25. Jumlah sudut dalam sebuah segitiga = 180°
Besar susut ABC = 180 – (4x + 10)
Besar sudut ACB = 180 – (5x + 5)
sudut ABC + sudut ACB + sudut BAC = 180°
↔ 180 – (4x + 10) + 180 – (5x + 5) + 60 = 180
↔ 180 – 4x – 10 + 180 – 5x – 5 + 60 = 180
↔ 180 – 10 + 180 – 5 + 60 – 180 = 4x + 5x
↔ 225 = 9x
↔ x = 225/9 = 25
Besar sudut ABC
= 180 – (4x + 10)
= 180 – 4x – 10
= 170 – 4(25)
= 170 – 100
= 70
Jawab: C
26 dan 27, gambar tidak jelas.