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M1.V1=M2.V2
M2= M1.V1/v2
=0.4.25/75
=4/10.1/3
=4/30 M
atau = 0.13 M :D
M₁ = 0,4 M
V₂ = 75 + 25 = 100 mL
M₂ = ............?
Penyelesaian :
Pakai rumus pengenceran
M₁ x V₁ = M₂ x V₂
0,4 x 25 = M₂ x 100
10 = M₂ x 100
M₂ = 10/100
M₂ = 0,1 M
Jadi, konsentrasinya akan menajdi 0,1 M