Question

Nilai log 3log81 + 4log16 + 5log 1/25 adalah

Answer 1

3log81 = 4

4log16 = 2

5log1/25 = -2

4 + 2 - 2
= 4
==========

pembuktian :

3log81 + 4log16 + 5log1/25
= 3log3^4 + 4log4^2 + (5log1 - 5log25)
= 4.3log3 + 2.4log4 + (0 - 5log5^2)
= 4 + 2 + (- 2.5log5)
= 4 + 2 + (-2.1)
= 4 + 2 - 2
= 4

Answer 2