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=2(2^2x) + 5(2^x) + 2
=2(2^x)^2 + 5(2^x) + 2
Misal 2^x = X sehingga:
2(x)^2 + 5(x) + 2
2x^2 - 5x + 2 = 0
(2x-1) (x-2) = 0
1. X = 1/2
2. x = 2
maka
1. 2^x = 1/2 shingga x = -1
2. 2^x = 2 shingga x = 1
jadi. jumlahnya
1 + (-1) = 0