3 akar 27 pangkat 2x-1 = (∛1/243)pangkat 3x
azharhadi
![(3 \sqrt{27} )^{2x-1}= (\sqrt[3]{ \frac{1}{243} })^{3x} \\ 3^{ \frac{5}{2}.(2x-1)}=3^{- \frac{5}{3}.3x} \\ 5x-5/2 = -5x \\ 5x+5x=5/2 \\ \\ 10x=5/2 x=5/2 / 10= 5/2 x 1/10=1/4](https://tex.z-dn.net/?f=%283+%5Csqrt%7B27%7D+%29%5E%7B2x-1%7D%3D+%28%5Csqrt%5B3%5D%7B+%5Cfrac%7B1%7D%7B243%7D+%7D%29%5E%7B3x%7D+%5C%5C+3%5E%7B+%5Cfrac%7B5%7D%7B2%7D.%282x-1%29%7D%3D3%5E%7B-+%5Cfrac%7B5%7D%7B3%7D.3x%7D+%5C%5C+5x-5%2F2+%3D+-5x+%5C%5C+5x%2B5x%3D5%2F2+%5C%5C+%5C%5C+10x%3D5%2F2+x%3D5%2F2+%2F+10%3D+5%2F2+x+1%2F10%3D1%2F4 "(3 \sqrt{27} )^{2x-1}= (\sqrt[3]{ \frac{1}{243} })^{3x} \\ 3^{ \frac{5}{2}.(2x-1)}=3^{- \frac{5}{3}.3x} \\ 5x-5/2 = -5x \\ 5x+5x=5/2 \\ \\ 10x=5/2 x=5/2 / 10= 5/2 x 1/10=1/4")
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