Odpowiedź:
3) A , B ; 2) B
3)
[tex]\displaystyle 3^5\cdot6^5\cdot(-0,5)^5=-(3\cdot6\cdot0,5)^5=-9^5=(-9)^5\\[/tex]
A, B
2)
[tex]\displaystyle \frac{(-16)^4}{2^4} = \frac{16^4}{2^4}=\frac{(2^4)^4}{2^4} =\frac{2^{16}}{2^4} =2^{16-4}=2^{12}=(2^3)^4=8^4[/tex]
B
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Odpowiedź:
3) A , B ; 2) B
3)
[tex]\displaystyle 3^5\cdot6^5\cdot(-0,5)^5=-(3\cdot6\cdot0,5)^5=-9^5=(-9)^5\\[/tex]
A, B
2)
[tex]\displaystyle \frac{(-16)^4}{2^4} = \frac{16^4}{2^4}=\frac{(2^4)^4}{2^4} =\frac{2^{16}}{2^4} =2^{16-4}=2^{12}=(2^3)^4=8^4[/tex]
B