Question

Diketahui cot A = 7/24 dengan A sudut lancip maka sec A + cosec A =

Answer 1

Cot A = 7/24.
cot A = x/y
r^2 = x^2+ y^2
r^2 = 7^2 + 24^2
r^2 = 49+576
r^2 = 626
r = √625
r = 25
sec A + cosec A = 25/7+25/24
= 600/168 + 175/168
= 775/168