IP Network IP pertama IP terakhir Broadcast 192.196.0.0 192.196.0.1 192.196.1.254 192.196.1.255 192.196.2.0 192.196.2.1 192.196.3.254 192.196.3.255 192.196.4.0 192.196.4.1 192.196.5.254 192.196.5.255 ................. ................. ................... ...................... 192.196.254.0 192.196.254.1 192.196.255.254 192.196.255.255
Jadi IP 192.168.3.121 terletak di subnet ke-2 dengan : IP Subnet / IP Network = 192.196.2.0 IP Pertama = 192.196.2.1 IP Terakhir = 192.196.3.254 IP Broadcast = 192.168.3.255
Semoga membantu... :)
1 votes Thanks 2
adeevaAbqari
iya .. makasih atas pemberitahuannya ^^
Brillianttt
baru kelas XI ya... kan ini CIDR .. nanti kalau kelas 3 pakai VLSM loh....
Netmask : 11111111.11111111.11111110.00000000 ----> 255.255.254.0
Jumlah subnet : 2⁷ = 128
Jumlah host / subnet = 2⁹ - 2 = 512 - 2 = 510
Blok subnet = 256 - 254 = 2
-----> 0,2,4,6,8,.....,254
IP Network = IP Subnet
IP Network IP pertama IP terakhir Broadcast
192.196.0.0 192.196.0.1 192.196.1.254 192.196.1.255
192.196.2.0 192.196.2.1 192.196.3.254 192.196.3.255
192.196.4.0 192.196.4.1 192.196.5.254 192.196.5.255
................. ................. ................... ......................
192.196.254.0 192.196.254.1 192.196.255.254 192.196.255.255
Jadi IP 192.168.3.121 terletak di subnet ke-2 dengan :
IP Subnet / IP Network = 192.196.2.0
IP Pertama = 192.196.2.1
IP Terakhir = 192.196.3.254
IP Broadcast = 192.168.3.255
Semoga membantu... :)