Question

Determina la ecuacion de la recta en forma general que pasa a travez de los puntos : (-12/5, 0) y (-3,-3/2)

Answer 1

[(X - X1)/(X2 - X1)] = [(Y - Y1)/(Y2 - Y1)]

Donde:  X1 = -12/5;  Y1 = 0;  X2 = -3;  Y2 = -3/2

 [(X - (-12/5))/(-3 - (-12/5)] = [(Y - 0)/(-3/2 - 0)]

 (X +12/5))/(-3/5) = (Y)/(-3/2)

-3/2(X +12/5) = -3/5(Y)

(-3/2)X - 18/5 = (-3/5)Y;  Divido toda la expresion entre -3/5

(5/2)X + 6 = Y

Y = (5/2)X + 6