2+2 =
ini tolong di jawab pke cara ekstrim jg boleh
ini tolong di jawab pke cara ekstrim jg boleh
bagusdarmawan58
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izharulhaq78
![2+2=\left[\begin{array}{ccc}\sqrt{\frac{\int\limit^2_02x^3\,dx}{\ln e^{^2\log4}}}}\end{array}\right]^2\\2+2=\left[\begin{array}{ccc}\frac{\frac{2}{3+1}x^{3+1}]^2_0}{\ln e^{2}}}\end{array}\right]\\2+2=\frac{\frac{2}{4}x^{4}]^2_0}{2}\\2+2=\frac{\frac{1}{2}x^{4}]^2_0}{2}\\2+2=\frac{\frac{1}{2}2^{4}-\frac{1}{2}0^{4}}{2}\\2+2=\frac{\frac{1}{2}(16)-0}{2}\\2+2=\frac{8}{2}\\\boxed{2+2=4}](https://tex.z-dn.net/?f=2%2B2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Csqrt%7B%5Cfrac%7B%5Cint%5Climit%5E2_02x%5E3%5C%2Cdx%7D%7B%5Cln+e%5E%7B%5E2%5Clog4%7D%7D%7D%7D%5Cend%7Barray%7D%5Cright%5D%5E2%5C%5C2%2B2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cfrac%7B%5Cfrac%7B2%7D%7B3%2B1%7Dx%5E%7B3%2B1%7D%5D%5E2_0%7D%7B%5Cln+e%5E%7B2%7D%7D%7D%5Cend%7Barray%7D%5Cright%5D%5C%5C2%2B2%3D%5Cfrac%7B%5Cfrac%7B2%7D%7B4%7Dx%5E%7B4%7D%5D%5E2_0%7D%7B2%7D%5C%5C2%2B2%3D%5Cfrac%7B%5Cfrac%7B1%7D%7B2%7Dx%5E%7B4%7D%5D%5E2_0%7D%7B2%7D%5C%5C2%2B2%3D%5Cfrac%7B%5Cfrac%7B1%7D%7B2%7D2%5E%7B4%7D-%5Cfrac%7B1%7D%7B2%7D0%5E%7B4%7D%7D%7B2%7D%5C%5C2%2B2%3D%5Cfrac%7B%5Cfrac%7B1%7D%7B2%7D%2816%29-0%7D%7B2%7D%5C%5C2%2B2%3D%5Cfrac%7B8%7D%7B2%7D%5C%5C%5Cboxed%7B2%2B2%3D4%7D "2+2=\left[\begin{array}{ccc}\sqrt{\frac{\int\limit^2_02x^3\,dx}{\ln e^{^2\log4}}}}\end{array}\right]^2\\2+2=\left[\begin{array}{ccc}\frac{\frac{2}{3+1}x^{3+1}]^2_0}{\ln e^{2}}}\end{array}\right]\\2+2=\frac{\frac{2}{4}x^{4}]^2_0}{2}\\2+2=\frac{\frac{1}{2}x^{4}]^2_0}{2}\\2+2=\frac{\frac{1}{2}2^{4}-\frac{1}{2}0^{4}}{2}\\2+2=\frac{\frac{1}{2}(16)-0}{2}\\2+2=\frac{8}{2}\\\boxed{2+2=4}")
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dimasdonigarci
biasa bgt ga greget , wkwkkw :) masih panjangan jawaban kmarin meskipun salah. dan krnapa jawaban mu ga dpet pringatan dari admin