Question

Tentukan penyelesaian dari:

1.)2t+21=3t-15
2.)3x+2/3=1/2(1+x)
3.)5+3(x-1)=10x-5

Answer 1

1.t=36 Pakai cara perpindahan ruas.
2. 
3.7x=7
x=1

Answer 2

Nomor 1 :
2t+21 = 3t-15
2t-3t = -15 - 21
    -t  = -36
     t  = 36

nomor 2
3x+2/3 = 1/2(1+x) .......>kedua ruas dikli 6
18x + 4 = 3(1+x)
18x + 4 = 3 + 3x
18x-3x = 3-4
     15x = -1
         x = -1/15

nomor 3 :
5+3(x-1)=10x-5
5+3x-3 = 10x - 5
3x-10x = -5-5+3
     -7x = -7
        x = 1