January 2019 2 35 Report
Sprawdzi mi ktoś czy to jest dobrze obliczone?
Oblicz zawartość procentową węgla w C15H30
Mc= 12*15=180 [u]
MH= 1*30=30[u]
180+30=210[u]
%C=180/210*100%=1800/21~85,71%

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