[tex]3 \frac{1}{4} + 2 - ( \frac{1}{ \cancel2} \times \cancel{10} ^{5} ) \\ \\ = \frac{13}{4} + \frac{2}{1} - \frac{5}{1} \\ \\ = \frac{13 + 8 - 20}{4} = \frac{1}{4} [/tex]
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[tex]3 \frac{1}{4} + 2 - ( \frac{1}{ \cancel2} \times \cancel{10} ^{5} ) \\ \\ = \frac{13}{4} + \frac{2}{1} - \frac{5}{1} \\ \\ = \frac{13 + 8 - 20}{4} = \frac{1}{4} [/tex]