Respuesta:
Explicación paso a paso:
[tex]\frac{h^{4}-81}{h-3}=h^{3}+3h^{2}+9h+27[/tex]
[tex]\frac{x^{15m-5n}-y^{25}}{x^{3m-n}y^{5}}=x^{12m-4n}+x^{9m-3n}y^{5}+x^{6m-2n}y^{10}+x^{3m-n}y^{15}+y^{20}[/tex]
[tex]\frac{x^{3}+27y^{3}}{x+3y}=x^{2}-3xy+9y^{2}[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
Respuesta:
Explicación paso a paso:
[tex]\frac{h^{4}-81}{h-3}=h^{3}+3h^{2}+9h+27[/tex]
[tex]\frac{x^{15m-5n}-y^{25}}{x^{3m-n}y^{5}}=x^{12m-4n}+x^{9m-3n}y^{5}+x^{6m-2n}y^{10}+x^{3m-n}y^{15}+y^{20}[/tex]
[tex]\frac{x^{3}+27y^{3}}{x+3y}=x^{2}-3xy+9y^{2}[/tex]