200 cm3 roztworu zawiera 0,05 mola KOH. Oblicz pH. Bardzo proszę opisać jak to sie robi!
200 cm3 roztworu zawiera 0,05 mola KOH. Oblicz pH. Bardzo proszę opisać jak to sie robi!
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V = 200cm3 = 0.2 dm3
n = 0.05mola KOH
Cm = n/V
Cm = 0.05 / 0.2
Cm = 0.25 mol/dm3
pOH = -log[OH-]
pOH = -log[0.25]
pOH = 0.60
14 = pH + pOH
pH = 14 - pOH
pH = 14 - 0.60
pH = 13.40