Se tienen 2 numeros consecutivos tales que la suma de 1/5 del mayor con 1/35 del menor excede 8 a los 3/20 del mayor
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1/5 (x+1) + 1/35 ( x) = 8 + 3/20 ( x+1)
4( 8x + 7 ) = 7 ( 163 + 3x)
32x + 28 = 1141 + 21x
11x = 1113
x = 101.18