2 X PANGKAT 2 - M X + 8 = 0 TOLONG Bntuin ya.... Question from @putrikarmila

September 2018 2 23 Report

2 X PANGKAT 2 - M X + 8 = 0

TOLONG Bntuin ya

dindajgshock A = 2 ; b = -m ; c = 8
D = 0
b²- 4ac = 0
(-m)² - 4×2×8 = 0
m² - 64 = 0
m² = 64
m = +/-√64
m1 = -8
m2 = 8
semoga membantu :)

1 votes Thanks 0

Mausuf $2x^2-mx+8=0$
Agar persamaan kuadrat tersebut memiliki akar real, maka haruslah:
$D \geq 0$
$b^2-4ac \geq 0$
$(-m)^2-4(1)(8) \geq 0$
$m^2-32 \geq 0$
$(m+4\sqrt{2})(m-4\sqrt{2}) \geq 0$
dengan menggunakan garis bilangan didapatkan :
$m \leq -4\sqrt{2}$ atau $m \geq 4\sqrt{2}$

0 votes Thanks 0

putrikarmila x pangkat 2 - 17p x + 10p = 0

putrikarmila tolong bantuin lgii yaa soalnya gk ngerti :) dn mksh yaa :)

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2 . tentukan nilai m agar persamaan berikut mempunyai 2 akar yang kembar / sama ? b. X PANGKAT 2 - 2M X - M - 1 = 0

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