Question

Sederhanakan
a.2/3 x 2log64-1/2 x 2log16
b.alog2x+3(alog x-alog y)

Answer 1

A. 2/3 x 6 - 1/2 x 4 = 4-2 =2
b. alog2x + alog[x^{3} [/tex]/[ y^{3} [/tex]
    alog2x X [x^{3} [/tex]/[ y^{3} [/tex]
    alog 2[x^{4} [/tex]/[ y^{3} [/tex]

Answer 2

2/3 x 2log 64 - 1/2 x 2log 16
= 2/3 x 2log 2pangkat 6 - 1/2 x 2log 2pangkat 4
=2/3 x 6 - 1/2 x 4
=12/3 - 4/2
=4-2
=2