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q=2,5 x10⁴μC =2,5.10⁴.10⁻⁶C=2,5.10⁻² C
Δv=120 volt
Ditanyakan: E=?
Dijawab:
Pakai rumus :
E=W=q.Δv
=2,5.10⁻².120
=3 Joule.
#Jangan lupa jadikan yang terbaik..............