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• Hk Pergeseran
T1 = T, λ1 = 6000 Å
T2 = (3/2) T, λ2 = ___?
Hukum pergeseran Wien
λ T = konstan
λ2 T2 = λ1 T1
λ2 = (T1 / T2) λ1
λ2 = [ T / (3/2 T)] • 6000
λ2 = ⅔ • 6000
λ2 = 4000 Å ← jwb
Ok ?