Suatu barisan geometri dengan suku pertama 16 dan suku ke enam 1/2 suku kedelapan barisan tersebut adalah....
Takamori37
![a=16 \\ U_6=ar^5=\frac{1}{2} \\ ar^5=\frac{1}{2} \\ 16r^5=\frac{1}{2} \\ r^5=\frac{1}{32} \\ r=\sqrt[5]{\frac{1}{32}}=\frac{1}{2} \\ \\ U_8=ar^7 \\ U_8=16\times(\frac{1}{2})^7 \\ U_8=16\times\frac{1}{128} \\ U_8=\frac{1}{8}](https://tex.z-dn.net/?f=a%3D16+%5C%5C+U_6%3Dar%5E5%3D%5Cfrac%7B1%7D%7B2%7D+%5C%5C+ar%5E5%3D%5Cfrac%7B1%7D%7B2%7D+%5C%5C+16r%5E5%3D%5Cfrac%7B1%7D%7B2%7D+%5C%5C+r%5E5%3D%5Cfrac%7B1%7D%7B32%7D+%5C%5C+r%3D%5Csqrt%5B5%5D%7B%5Cfrac%7B1%7D%7B32%7D%7D%3D%5Cfrac%7B1%7D%7B2%7D+%5C%5C+%5C%5C+U_8%3Dar%5E7+%5C%5C+U_8%3D16%5Ctimes%28%5Cfrac%7B1%7D%7B2%7D%29%5E7+%5C%5C+U_8%3D16%5Ctimes%5Cfrac%7B1%7D%7B128%7D+%5C%5C+U_8%3D%5Cfrac%7B1%7D%7B8%7D "a=16 \\ U_6=ar^5=\frac{1}{2} \\ ar^5=\frac{1}{2} \\ 16r^5=\frac{1}{2} \\ r^5=\frac{1}{32} \\ r=\sqrt[5]{\frac{1}{32}}=\frac{1}{2} \\ \\ U_8=ar^7 \\ U_8=16\times(\frac{1}{2})^7 \\ U_8=16\times\frac{1}{128} \\ U_8=\frac{1}{8}")
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